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7x^2+35x=252
We move all terms to the left:
7x^2+35x-(252)=0
a = 7; b = 35; c = -252;
Δ = b2-4ac
Δ = 352-4·7·(-252)
Δ = 8281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8281}=91$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-91}{2*7}=\frac{-126}{14} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+91}{2*7}=\frac{56}{14} =4 $
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